 # How Many Possibilities Are There With 16 Numbers?

## How many combinations are there with 11 numbers?

99 combinations2.

See for 11 numbers there can be 9 ways for each number for 1st nine places since 0 can’t be the fist number and next two are repeated from 10 numbers hence 10!/2.

So 99 combinations have 10!/2.

Permutations hence total ways are 99*10!/2!.

## How many combinations of 6 numbers are there in 59?

45,057,474The number of combinations possible with 6 numbers between 1 and 59 is 45,057,474.

## How many combinations of 3 numbers are there?

Assuming the digits 0 through 9 can be used, and a number can be repeated in the combination, then there are 10^3 possible combinations (1000 – from 000 to 999). If three different numbers have to be used, then 10 x 9 x 8 = 720 possible combinations.

## How many combinations of 7 numbers are there?

Assuming repetition is allowed, you can have 7-digit numbers from 1,000,000 to 9,999,999 which is a total of 9,000,000 7-digit numbers. These are all the possible 7-digit numbers. In general, there are 9 × 10^(n-1) possible n-digit numbers.

## How do you calculate permutations?

The number of permutations of n objects taken r at a time is determined by the following formula: P(n,r)=n! (n−r)! A code have 4 digits in a specific order, the digits are between 0-9.

## How many combinations of 6 items are there?

720 possible combinationsWith 1 item there are 6 possibilities with 2 you only have 5 choices after the first if you don’t repeat the same item. So for 6 items the equation is as follows 6*5*4*3*2= 720 possible combinations of 6 items.

## How do you calculate the number of possible combinations?

Remember that combinations are a way to calculate the total outcomes of an event where order of the outcomes does not matter. To calculate combinations, we will use the formula nCr = n! / r! * (n – r)!, where n represents the number of items, and r represents the number of items being chosen at a time.

## How many combinations of 60 numbers are there?

10 10 10 = 1000 three digit combinations. There are 60 of them. Using the same argument as above there are 60 60 = 3600 two “digit” combinations and 60 60 60 = 216000 three “digit” combinations.

## How many 4 letter combinations are there?

256This is a case of number of arrangements possible with repetition. Thus you have 4 options each for the 1st,2nd,3rd and 4th letter giving you a total of 4*4*4*4 = 256 number of possible combinations.

## How many pairs can you make with 12 numbers?

If repetition of digits is not allowed then the number of combinations possible is 12P12. That is 12! Combinations. So 479001600 combinations are possible if repetition is not allowed.

## What is the R in nPr?

subset sizen = the set size. It is the total number of items in the sample. r = the subset size. It is the number of items chosen from the sample.

## How many permutations of 4 numbers are there?

It also means that when we selected one item (four choices), we created four different combinations with three items. Now we now all of the combinations and can add them up: 1 + 4 + 6 + 1 + 4 = 16 different possibilities. A related topic to combinations is “permutations”.

## How many possibilities are there with 2 numbers?

[You don’t want to include (40,20) and (20, 40).] So that means you need to know how many different permutations there are for each combination. If there are two numbers, there are two permutations per combination. Divide the possible permutations by number of permutations per combination: 2450 / 2 = 1225.

## What is nPr formula?

nPr(n, r) The number of possibilities for choosing an ordered set of r objects (a permutation) from a total of n objects. Definition: nPr(n,r) = n! / (n-r)! nCr(n, r)

## How many combinations of 50 numbers are there?

Included with Your Order: All Possible 5/50 Number Combinations. Total Combinations – 2,118,760.

## How many 4 number combinations are there?

There are 10,000 possible combinations that the digits 0-9 can be arranged into to form a four-digit code.

## What is nPr and NCR in math?

In NCR and NPR, C stands for Combinations, and P stands for permutations. Now for combinations, it is the number of ways you can pick r objects out of n. In permutations, it is the number of ways you can pick r objects out of n and then arrange them. … Therefore, NPR= NCR*r!

## How many combinations of 1000 numbers are there?

Each time you get 100 possible combinations so all together you have 10 × 100 = 10 × 10 × 10 = 1,000 possible combinations.

## What are all the possible combinations of 1234?

If you wager on 1234 boxed, you would win if any of the following combinations were drawn: 1234, 1243, 1324, 1342, 1423, 1432, 2134, 2143, 2314, 2341, 2413, 2431, 3124, 3142, 3214, 3241, 3412, 3421, 4123, 4132, 4213, 4231, 4312, or 4321.

## How many combinations of 5 are there?

Thus you have made 5 × 4 × 3 × 2 1 = 120 choices and there are 120 possible 5 digit numbers made from 1, 2, 3, 4 and 5 if you don’t allow any digit to be repeated. Now consider the possibilities with 13 as the first two digits.

## How many combinations of 100 numbers are there?

Given 100, choose 99, there are 100 combinations. Given 100, choose 98, there are 161,700 combinations. The number of combinations gets bigger fast. 100, choose 95, is over 7 million combinations.